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The projectile is the object while the path taken by the projectile is known as a trajectory.

Range of a projectile formula. The horizontal range depends on the initial velocity v 0 the launch angle θ and the acceleration due to gravity. The range of the motion is fixed by the condition y 0 y 0. This horizontal range is given by the relation So the.

The range of the projectile is the total horizontal distance traveled during the flight time. The velocity components and are given by the formula. Suppose a projectile is thrown from the ground level then the range is thedistance between the launch point and the landing point where the projectilehits the ground.

Range The range of a projectile motion is the total distance travelled horizontally. R u2 sin2θ g R u 2 sin 2 θ g. The horizontal range of a projectile is the distance along the horizontal plane it would travel before reaching the same vertical position as it started from.

50 and g is The height of the projectile is given by the component y and it reaches its maximum value when the component is equal to zero. Derivation of the Horizontal Range Formula Most of the basic physics textbooks talk on the topic of horizontal range of the Projectile motion. Let us consider a projectile projected with initial velocity making an angle with the horizontal as shown below in the figure.

Quick derivation of the range formula for projectile motion. The range of a projectile depends on its initial velocity denoted as u and launch angle theta. Therefore we derive it using the kinematics equations.

So the formula of the horizontal range of a projectile is R V02 sin2θ g. Again if were launching the object from the ground initial height 0 then we can write the formula as R Vx t Vx 2 Vy g. Also note that range is maximum when 45 as sin 2 sin 90 1.

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